NEET Exam Challenge: Counting pπ-pπ & pπ-dπ Bonds in 10 Minutes for 4 Marks

by | Sep 21, 2023 | TIPS Bonds | 13 comments

NEET Exam Challenge: Counting pπ-pπ & pπ-dπ Bonds in 10 Minutes for 4 Marks




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Number of pπ-pπ & pπ-dπ Bonds || 4 Marks in 10 Minutes For NEET Exam

When it comes to the NEET exam, every mark matters. Therefore, it is crucial to have a good grasp on all the important topics, including the number of pπ-pπ and pπ-dπ bonds. In this article, we will discuss these bonds and how to calculate their numbers, providing you with valuable information to ace your exam.

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Firstly, let’s understand what pπ-pπ and pπ-dπ bonds are. These types of bonds occur in organic compounds and are formed due to the overlapping of p-orbitals. pπ-pπ bonds are formed between two atoms when one atom has an unhybridized p orbital and the other atom has a π bond in one of its p orbitals. This type of bond is commonly seen in alkene compounds. On the other hand, pπ-dπ bonds are formed between a p orbital and a d orbital. This bond type is commonly found in transition metal complexes.

Calculating the number of pπ-pπ bonds is relatively straightforward. Since each alkene molecule consists of one double bond, the number of pπ-pπ bonds is equal to the number of alkene molecules present in a compound. For example, in a compound with three alkene molecules, the total number of pπ-pπ bonds would be three.

To calculate the number of pπ-dπ bonds, we need to consider the coordination number of the central atom. The coordination number represents the number of bonds formed by the central atom. Transition metals usually have a coordination number ranging from 2 to 9. To determine the number of pπ-dπ bonds, we subtract the coordination number from the total number of bonds formed by the central atom. This difference represents the number of pπ-dπ bonds.

Let’s take an example to better understand this calculation. In a transition metal complex with a coordination number of 6 and a total of 8 bonds formed by the central atom, the number of pπ-dπ bonds would be 8 – 6 = 2.

It is important to note that these calculations may vary depending on the complexity of the compound and the presence of other functional groups. Therefore, it is advisable to practice these calculations on different examples to build a better understanding.

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To maximize your chances of scoring well in the NEET exam, it is essential to not just memorize the formulas and calculations, but also to understand the underlying concepts. This will enable you to apply your knowledge to a wide range of questions with confidence.

In conclusion, the number of pπ-pπ and pπ-dπ bonds is an important topic for the NEET exam. By understanding the concepts and practicing the calculations, you can confidently answer questions related to these bonds, securing valuable marks in your exam. Remember to allocate sufficient time for practicing and revising this topic to ensure a strong foundation in organic chemistry. Good luck!

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13 Comments

  1. Khushi bajaj

    Can we say no of pie bond=no of p pi – d pi bond??? Plz tell anyone

  2. Renu Bhugra

    Thanku so much sir ❤

  3. Aparna

    Sir kha hai aapke charan

  4. Mehebub Laskar

    Structure given in question??? Or not

  5. Md Owais Nathani

    I was unable to understand how much p pi and d pi and etc now it is crystal clear. ❤❤

  6. Prem Kr. Poddar

    Jee wale hai hum ,,par now concept clear

  7. Jyoti Swami

    Sir structure nhi pta ho to hm kese count krenge

  8. wakuwaku98

    Sp3 hybrid no pi bond

  9. SWETA BHANJA

    Rest two d orbit kanha se aye sp3 he to 1 s +3p

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